Lenovo ThinkCentre E51 (Traditional Chinese) User guide - Page 58
MNP/V.42/V.42bis/V.44
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ⁿO +MS=a,b,c,e,f MNP/V.42/V.42bis/V.44 ⁿO ⁿO %C_ &Q_ +DS44=0, 0 +DS44=3, 0 +DS44? +DS44=? %C0 %C1 %C2 %C3 &Q0 &Q5 &Q6 \α ∩ AΣñGa=0B 1B2B3B9B10B11B12B56B64B69Fb=0-1F c=300-56000Fd=300-56000F e=0-1F f=0-1CABbBcBdBeBf w] = 12B1B300B56000B0B0C ″a″ ⁿw qT≤wAΣñG 0=V.21B1=V.22B2=V.22bisB 3=V.23B9=V.32B10=V.32bisB11=V.34B 12=V.90,K56Flex,V.34......B 56=K 56Flex,V.90,V.34......B64=Bell 103A 69=Bell 212C ″b″ ⁿw í@ AΣñG0= íA1= H V.8/V.32 Annex A íC ″c″ ⁿw psuΩ ev (300- 56000)C ″d″ ⁿw jsutv (300-56000)F ″e″ hⁿw codec ¼]0= LawA 1=A-Law C ″f″ ⁿwuT v(robbed bit) T ]0= A1= \α MNP Class 5 P V.42bis Ω úY MNP Class 5 Ω úY V.42bis Ω úY MNP Class 5 P V.42bis Ω úY Ω ]Ñ≤ \N1 V.42 Ω H t∩ @δΩ ]Ñ≤ \N0 V.44 V.44 {μ Σ Mμ 42 ΓU
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ⁿ
O
\
α
+MS=a,b,c,e,f
∩
³
´
±
A
Σ
ñ
G
a
=0
B
1
B
2
B
3
B
9
B
10
B
11
B
12
B
56
B
64
B
69
F
b
=0-1
F
c
=300-56000
F
d
=300-56000
F
e
=0-1
F
´
f
=0-1
C
A
B
b
B
c
B
d
B
e
B
f
w
]
À
=
12
B
1
B
300
B
56000
B
0
B
0
C
´
±
″
a
″
ⁿ
w´
±
±
´
±
q
T
≤
w
A
Σ
ñ
G
0=V.21
B
1=V.22
B
2=V.22bis
B
3=V.23
B
9=V.32
B
10=V.32bis
B
11=V.34
B
12=V.90,K56Flex,V.34
......
B
56=K
56Flex,V.90,V.34
......
B
64=Bell 103
A
´
69=Bell
212
C
´
±
″
b
″
ⁿ
w
µ
±
·
í
@
¶
A
Σ
ñ
G
0=
µ
±
µ
±
·
í
A
1=
H
V.8/V.32 Annex A
µ
±
µ
±
·
í
C
´
±
″
c
″
ⁿ
w
´
p
s
u
Ω
¹
³
e
v
(300-
56000)
C
´
±
″
d
″
ⁿ
w
´
j
s
u
t
v
(300-56000)
F
´
´
±
″
e
″
hⁿ
w
codec
³
¼
]
0=
Law
A
´
1=A-Law
±C
´
±
″
f
″
ⁿ
w
u
T
±
»
³
v
(robbed bit)
T
µ
½
·
]
0=
µ
±
½
·
A
1=
µ
±
½
·
±
MNP/V.42/V.42bis/V.44
ⁿ
O
ⁿ
O
\
α
%C_
%C0
µ
±
MNP Class 5
P
V.42bis
Ω
¹
ú
Y
%C1
·
µ
±
MNP Class 5
Ω
¹
ú
Y
%C2
·
µ
±
V.42bis
Ω
¹
ú
Y
%C3
²
²
MNP Class 5
P
V.42bis
Ω
µ
ú
Y
&Q_
&Q0
·
³
¶
³
Ω
¹
µ
±
]
Ñ
≤
\N1
±
&Q5
V.42
Ω
µ
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³
H
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t
²
∩
±
&Q6
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@
δ
Ω
¹
µ
±
]
Ñ
≤
\N0
±
+DS44=0, 0
µ
±
V.44
+DS44=3, 0
µ
±
V.44
+DS44?
{
μ
À
+DS44=?
Σ
±
À
±
M
μ
42
±
±
Γ
U