Bosch NET5054UC Instructions for Use - Page 9

<5=5>Dc, 5c94e1&lt - 30

Page 9 highlights

The elements Single element Single elements have only one size cooking surface. Choose a pan that matches the size of the element. Dual element Bridge element The size of these elements can be matched to your pan size. The heating element must be turned on. Turning off the outer heating ribbon: Touch ö. The ð display will turn off. Adding: Touch ö again. The ð display will turn on. The Bridge element combines two individual heating elements into one long griddle zone. This configuration is ideal for griddles and large pans. Note:ĄDo not use cookware larger than 17" x 10" (432 x 254 mm). Turning on the Bridge element: Touch one of the two $ symbols for selecting the heating element, then touch à. The ø symbol will appear; both heating elements are now selected. 0 appears in both displays. Within the next 10 seconds select the desired heat setting (1Ć9). The Bridge element and both individual heating elements are now on. Changing the heat setting: Touch one of the two $ symbols for selecting the bridge element, and set the new heat level within the next 10 seconds. Turning off the Bridge element feature: Touch one of the two $ symbols for selecting the bridge element, and in the setting area set the value to 0. 0 appears in both displays. The heating elements will turn off and the residual heat indicator will appear. Residual heat indicator The cooktop has a hot surface indicator for each element. It shows you which elements are still hot. The hot surface indicator has two levels. If an H is shown on the display, the element is still hot. You could use it, for example, to keep a small quantity of food warm or to melt a chocolate coating. As the element continues to cool, the display changes to h. The display goes out once the element has cooled sufficiently. The hot surface indicator will automatically come on after a power failure. The display lights up for approximately 30 minutes. 9

  • 1
  • 2
  • 3
  • 4
  • 5
  • 6
  • 7
  • 8
  • 9
  • 10
  • 11
  • 12
  • 13
  • 14
  • 15
  • 16
  • 17
  • 18
  • 19
  • 20
  • 21
  • 22
  • 23
  • 24
  • 25
  • 26
  • 27
  • 28
  • 29
  • 30
  • 31
  • 32
  • 33
  • 34
  • 35
  • 36
  • 37
  • 38
  • 39
  • 40
  • 41
  • 42
  • 43
  • 44
  • 45
  • 46
  • 47
  • 48
  • 49
  • 50
  • 51
  • 52
  • 53
  • 54
  • 55
  • 56
  • 57
  • 58
  • 59
  • 60
  • 61
  • 62
  • 63
  • 64
  • 65
  • 66
  • 67
  • 68

¼
,<A:?³ ³?³@³AGF
;²I³ BA?L BA³ F<M³ ±BB><A:
FHE´²±³.
C;BBF³ ²
c²A
G;²G
@²G±;³F
G;³ F<M³ B´
G;³ ³?³@³AG.
-;³ F<M³ B´
G;³F³ ³?³@³AGF
±²A
·³ @²G±;³µ
GB
LBHE
c²A
F<M³.
-;³ ;³²G<A:
³?³@³AG
@HFG ·³ GHEA³µ
BA.
-HEA<A:
B´´
G;³ BHG³E
;³²G<A:
E<··BAÀ
-BH±;
ö
.
-;³
ð
µ<Fc?²L J<?? GHEA
B´´.
aµµ<A:À
-BH±;
ö
²:²<A.
-;³
ð
µ<Fc?²L J<?? GHEA
BA.
-;³ bE<µ:³ ³?³@³AG
±B@·<A³F
GJB
<Aµ<I<µH²? ;³²G<A:
³?³@³AGF
<AGB
BA³ ?BA:
:E<µµ?³
MBA³.
-;<F
±BA´<:HE²G<BA
<F
<µ³²? ´BE
:E<µµ?³F
²Aµ
?²E:³ c²AF.
$?D5:
lDB ABG
HF³ ±BB>J²E³ ?²E:³E
G;²A
17" K
10" (432
K
254
@@).
-HEA<A:
BA
G;³ bE<µ:³ ³?³@³AGÀ
-BH±;
BA³ B´
G;³ GJB
$
FL@·B?F
´BE
F³?³±G<A:
G;³ ;³²G<A:
³?³@³AG¹
G;³A
GBH±;
à
.
-;³
ø
FL@·B? J<?? ²cc³²EÂ
·BG;
;³²G<A:
³?³@³AGF
²E³ ABJ F³?³±G³µ.
0
²cc³²EF
<A
·BG;
µ<Fc?²LF.
¸<G;<A
G;³ A³KG
10
F³±BAµF
F³?³±G
G;³ µ³F<E³µ
;³²G
F³GG<A:
(1m9). -;³
bE<µ:³ ³?³@³AG
²Aµ
·BG;
<Aµ<I<µH²? ;³²G<A:
³?³@³AGF
²E³ ABJ BA.
C;²A:<A: G;³ ;³²G
F³GG<A:À
-BH±;
BA³ B´
G;³ GJB
$
FL@·B?F
´BE
F³?³±G<A:
G;³ ·E<µ:³ ³?³@³AG¹
²Aµ F³G G;³ A³J
;³²G ?³I³? J<G;<A
G;³ A³KG
10
F³±BAµF.
-HEA<A:
B´´
G;³ bE<µ:³ ³?³@³AG
´³²GHE³À
-BH±;
BA³ B´
G;³ GJB
$
FL@·B?F
´BE
F³?³±G<A:
G;³ ·E<µ:³ ³?³@³AG¹
²Aµ
<A
G;³ F³GG<A:
²E³² F³G G;³ I²?H³ GB
0.
0
²cc³²EF
<A
·BG;
µ<Fc?²LF.
-;³ ;³²G<A:
³?³@³AGF
J<??
GHEA
B´´
²Aµ G;³ E³F<µH²? ;³²G
<Aµ<±²GBE
J<?? ²cc³²E.
-;³ ±BB>GBc
;²F
² ;BG
FHE´²±³ <Aµ<±²GBE
´BE
³²±;
³?³@³AG.
»G
F;BJF
LBH
J;<±;
³?³@³AGF
²E³ FG<?? ;BG.
-;³ ;BG
FHE´²±³ <Aµ<±²GBE
;²F
GJB
?³I³?F.
»´
²A
H
<F
F;BJA
BA
G;³ µ<Fc?²L¹
G;³ ³?³@³AG
<F
FG<?? ;BG.
ÁBH
±BH?µ
HF³ <G¹ ´BE ³K²@c?³¹
GB
>³³c ² F@²?? dH²AG<GL B´
´BBµ
J²E@
BE
GB
@³?G
² ±;B±B?²G³ ±B²G<A:.
aF
G;³ ³?³@³AG
±BAG<AH³F
GB
±BB?¹
G;³ µ<Fc?²L ±;²A:³F
GB
h
.
-;³ µ<Fc?²L :B³F
BHG
BA±³ G;³ ³?³@³AG
;²F
±BB?³µ
FH´´<±<³AG?L.
-;³ ;BG FHE´²±³ <Aµ<±²GBE
J<?? ²HGB@²G<±²??L ±B@³ BA
²´G³E
² cBJ³E
´²<?HE³. -;³
µ<Fc?²L ?<:;GF
Hc
´BE
²ccEBK<@²G³?L 30Ã@<AHG³F.
*·5
5<5=5>Dc
)9>¶<5 5<5=5>D
de1<
5<5=5>D
bB94¶5
5<5=5>D
(5c94e1<
·51D 9>49³1D?B