HP 33s hp 33s_user's manual_English_E_HDPM20PIE56.pdf - Page 126

Sine Integral., sin

Page 126 highlights

Now calculate J0(3) with the same limits of integration. You must respecify the limits of integration (0, π) since they were pushed off the stack by the subsequent division by π. Keys: Display: Description: 0‘|N |H | T 3g |Nq )   1%º 1!22 ³  G_  . )  Enters the limits of integration (lower limit first). Displays the current equation. Prompts for the variable of integration. Prompts for value of X. x = 3. Starts integrating and calculates the result for π ³ f (t) . 0 The final result for J0(3). Example: Sine Integral. Certain problems in communications theory (for example, pulse transmission through idealized networks) require calculating an integral (sometimes called the sine integral) of the form ³ Si (t ) = t ( sin x )dx 0x Find Si (2). Enter the expression that defines the integrand's function: sin x x If the calculator attempted to evaluate this function at x = 0, the lower limit of integration, an error would result. However, the integration algorithm normally does not evaluate functions at either limit of integration, unless the endpoints of the interval of integration are extremely close together or the number of sample points is extremely large. 8-4 Integrating Equations

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8–4
Integrating Equations
Now calculate
J
0
(3) with the same limits of integration. You must respecify the
limits of integration (0,
π
) since they were pushed off the stack by the subsequent
division by
π
.
Keys:
Display:
Description:
0
Enters the limits of integration
(lower limit first).
Displays the current equation.
_
Prompts for the variable of
integration.
T
Prompts for value of
X
.
3
x
= 3. Starts integrating and
calculates the result for
π
0
)
(
t
f
.
The final result for
J
0
(3).
Example:
Sine Integral.
Certain problems in communications theory (for example, pulse transmission
through idealized networks) require calculating an integral (sometimes called the
sine
integral) of the form
dx
x
x
t
S
t
i
)
sin
(
)
(
0
=
Find
Si
(2).
Enter the expression that defines the integrand's function:
x
x
sin
If the calculator attempted to evaluate this function at
x
= 0, the lower limit of
integration, an error (
) would result. However, the integration
algorithm normally does
not
evaluate functions at either limit of integration, unless
the endpoints of the interval of integration are extremely close together or the
number of sample points is extremely large.