Texas Instruments voyage 200 User Manual - Page 885
taylor, the inverse hyperbolic tangent of each element.
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tanh( ) MATH/Hyperbolic menu tanh(expression1) ⇒ expression tanh(list1) ⇒ list tanh(expression1) returns the hyperbolic tangent of the argument as an expression. tanh(1.2) ¸ tanh({0,1}) ¸ .833... {0 tanh(1)} tanh(list) returns a list of the hyperbolic tangents of each element of list1. tanh(squareMatrix1) ⇒ squareMatrix Returns the matrix hyperbolic tangent of squareMatrix1. This is not the same as calculating the hyperbolic tangent of each element. For information about the calculation method, refer to cos(). In Radian angle mode: tanh([1,5,3;4,2,1;6,ë 2,1]) ¸ ë.4.8089...7... .933... .538... .425... ë.129... 1.282... ë 1.034... .428... squareMatrix1 must be diagonalizable. The result always contains floating-point numbers. tanhê ( ) MATH/Hyperbolic menu tanhê (expression1) ⇒ expression tanhê (list1) ⇒ list tanhê (expression1) returns the inverse hyperbolic tangent of the argument as an expression. tanhê (list1) returns a list of the inverse hyperbolic tangents of each element of list1. In rectangular complex format mode: tanhê (0) ¸ 0 tanhê ({1,2.1,3}) ¸ {ˆ .518... ì 1.570...ø i ln(2) 2ì p2ø i} tanhê(squareMatrix1) ⇒ squareMatrix Returns the matrix inverse hyperbolic tangent of squareMatrix1. This is not the same as calculating the inverse hyperbolic tangent of each element. For information about the calculation method, refer to cos(). In Radian angle mode and Rectangular complex format mode: tanhê([1,5,3;4,2,1;6,ë 2,1]) ¸ squareMatrix1 must be diagonalizable. The result always contains floating-point numbers. taylor( ) MATH/Calculus menu taylor(expression1, var, order[, point]) ⇒ expression Returns the requested Taylor polynomial. The polynomial includes non-zero terms of integer degrees from zero through order in (var minus point). taylor() returns itself if there is no truncated power series of this order, or if it would require negative or fractional exponents. Use substitution and/or temporary multiplication by a power of (var minus point) to determine more general power series. taylor(e^(‡(x)),x,2) ¸ taylor(e^(t),t,4)|t=‡(x) ¸ taylor(1/(xù (xì 1)),x,3) ¸ point defaults to zero and is the expansion point. expand(taylor(x/(xù(xì1)), x,4)/x,x) ¸ Appendix A: Functions and Instructions 887