Canon C50FSi Network Video Recorder VK-64/VK-16 Administrator's Manual - Page 32
Determining Required Hard Disk Capacity
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System Design Concept ● Determining Required Hard Disk Capacity Determine the required hard disk capacity as follows. 1 Determine the required number of Camera Servers and required video data size. 2 Select the Image Quality of each Camera Server. The video quality improves in proportion to the set value, but the data volume also becomes larger. 3 Determine the frame rate for recording video (i.e., the number of frames per second). For general security purposes, 1 to 2 fps is common. Higher frame rate requires more hard disk space. 4 Determine the recording period per day and duration to retain data. 5 After determining the conditions above, calculate the required hard disk capacity due to the video data size (in KB). Refer to "Example of frame sizes with VB-C60", "Example of frame sizes with VB-C300" and "Example of frame sizes with VB-C50i" (➝ P. 33). 6 If you record audio, to calculate the amount of hard disk space required for the audio data. The data size for recording audio is 8 KB/s regardless of the type of Camera Server. When determining hard disk sizes it is important to take into account that there needs to be considered about 10 to 20% additional room. Example 1: JPEG recording - Using 16 Camera Servers (VB-C60) for recording, - With each camera set to Medium Size for video data size and Image Quality set to 50 (data size per 1 frame: 15KB), - Recording frame rate is set at 2 fps, and - Data size per second is approximately 30 KB (= 15 KB x 2fps). Although actual data size depends on objects shot by each Camera Server, this calculation assumes the typical size shown above. - Audio recording as also performed simultaneously on 2 of the Camera Servers. For the above configuration, when JPEG images from 16 camera servers are being recorded continuously at 2 frames per second all day, every day, the required hard disk space is approximately 40GB per day (=30KB x 16 cameras x 60 seconds x 60 minutes x 24 hours = 41472000KB per day). 32