Casio FX-CG10 Software User Guide - Page 117
minimum value in a list, To calculate the mean of data items
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u To find the minimum value in a list [OPTN]-[LIST]-[Min] K1(LIST)6(g)1(Min)6(g)6(g)1(List) )w Example To find the minimum value in List 1 (36, 16, 58, 46, 56) AK1(LIST)6(g)1(Min) 6(g)6(g)1(List)b)w u To find which of two lists contains the greatest value [OPTN]-[LIST]-[Max] K1(LIST)6(g)2(Max)6(g)6(g)1(List) ,1(List) )w • The two lists must contain the same number of data items. If they don't, an error occurs. • The result of this operation is stored in ListAns Memory. Example To find whether List 1 (75, 16, 98, 46, 56) or List 2 (35, 59, 58, 72, 67) contains the greatest value K1(LIST)6(g)2(Max) 6(g)6(g)1(List)b, 1(List)c)w u To calculate the mean of data items [OPTN]-[LIST]-[Mean] K1(LIST)6(g)3(Mean)6(g)6(g)1(List) )w Example To calculate the mean of data items in List 1 (36, 16, 58, 46, 56) AK1(LIST)6(g)3(Mean) 6(g)6(g)1(List)b)w u To calculate the median of data items of specified frequency [OPTN]-[LIST]-[Med] This procedure uses two lists: one that contains values and one that indicates the frequency (number of occurrences) of each value. The frequency of the data in Cell 1 of the first list is indicated by the value in Cell 1 of the second list, etc. • The two lists must contain the same number of data items. If they don't, an error occurs. K1(LIST)6(g)4(Med)6(g)6(g)1(List) ,1(List) )w 3-10